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If you notice any errors, feel free to correct them.
Module:MonsterOnDay
From Super Fantasy Kingdom Official Wiki
Calculates on which days a monster appears first when the monster appearing rank is given (the day on the first appearance on curse 0 ignoring offsets by bosses) depending on on the curse level and the fixed boss days.
- When a monster on curse 0 appears first on day 1 the rank is 1
- When a monster on curse 0 appears first on day 8 the rank is 7 because the boss on day 7 is fixed without rank
{{MonsterOnDay|9}}
Lua error at line 32: attempt to call global 'table' (a table value).
-- calculates on which days a monster appears first
-- when the monster appearing rank is given (the day on the first appearance on curse 0 ignoring offsets by bosses)
-- depending on
-- on the curse level and
-- the fixed boss days
-- e.g. when a monster on curse 0 appears first on day 1 the rank is 1
-- e.g. when a monster on curse 0 appears first on day 8 the rank is 7 because the boss on day 7 is fixed without rank
local p = {}
function p.calculate(f)
local args = f:getParent().args
local rank = tonumber(args['1'])
if rank == nil then
return (args['1'] or 'nil') .. ' is not a valid number for a appearance rank'
end
local displayDaysForCurse = {0, 1, 2, 3, 4, 5}
local dayRows = {}
for curse,_ in ipairs(displayDaysForCurse) do
local dayForCurse = rank - curse
-- bosses appear on day 7 and 14, the monster day then is one day later
if dayForCurse >= 7 then dayForCurse = dayForCurse + 1 end
if dayForCurse >= 14 then dayForCurse = dayForCurse + 1 end
if dayForCurse < 1 then dayForCurse = '-' end
table.insert(dayRows, '<tr><td>[[File:Curse.png|16x16px|link=Curse]] [[Curse|C'..curse..']]</td><td>'..dayForCurse..'</td></tr>')
end
return '<table class=plaintable">'..table(concat, '')..'</table'
end
return p


